Question

2(x ^ 2 - x) - x(x + 2) + 4 = 0

Cíu tui zới aaaa

 

 

Answer 1

`=> 2x^2 - 2x - x^2 - 2x + 4 = 0`

`=> x^2 - 4x + 4 = 0`

`=> (x-2)^2 = 0`

`=> x - 2 = 0`

`=> x = 2.`

Vậy `x = 2`

Answer 2

2(x ^ 2 - x) - x(x + 2) + 4 = 0

<=> 2x^2 -2x -x^2-2x+4=0

<=> x^2 -4x + 4= 0

<=> (x-2)^2=0

<=> x-2=0

<=> x= 2

Answer 3

`2(x^2-x)-x(x+2)+4=0`

`<=>2x^2-2x-x^2-2x+4=0`

`<=>x^2-4x+4=0`

`<=>(x-2)^2=0`

`<=>x-2=0`

`<=>x=2`

Vậy `S={2}`

Answer 4

\(\Leftrightarrow2x^2-2x-x^2-2x+4=0\)

\(\Leftrightarrow x^2-4x+4=0\)

\(\Leftrightarrow\left(x-2\right)^2=0\)

\(\Rightarrow x-2=0\)

\(\Leftrightarrow x=2\)

Vậy x = 2 

Answer 5

2 (x² - x) - x(x + 2) + 4 = 0

=> 2x² - 2x - x² - 2x + 4 = 0

=> x² - 4x + 4 = 0

=> (x - 2)² = 0

=> x - 2 = 0

=> x = 2

vậy x = 2

Answer 6