\(\left(2x-1\right)^2-\left(x+3\right)^2=0\)
\(=>\left(2x-1+x+3\right)\left(2x-1-x-3\right)=0\)
\(=>\left(3x+2\right)\left(x-4\right)=0\)
\(=>\left[{}\begin{matrix}3x+2=0\\x-4=0\end{matrix}\right.\)
\(=>\left[{}\begin{matrix}3x=-2\\x=4\end{matrix}\right.\)
\(=>\left[{}\begin{matrix}x=\dfrac{-2}{3}\\x=4\end{matrix}\right.\)
\(=>x\in\left\{\dfrac{-2}{3};4\right\}\)
\(\left(2x-1\right)^2-\left(x+3\right)^2=0\)(sửa đề)
\(\Leftrightarrow\left(2x-1-x-3\right)\left(2x-1+x+3\right)=0\)
\(\Leftrightarrow\left(x-4\right)\left(3x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\3x+2=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-\dfrac{2}{3}\end{matrix}\right.\)
