\(2\cos4x+4\sin2x.\cos2x-\sqrt{2}=0\\ < =>2.\cos4x+2.\sin4x=\sqrt{2}\\ < =>2\sqrt{2}\sin\left(x+\dfrac{\pi}{4}\right)=\sqrt{2}\\ < =>\sin\left(4x+\dfrac{\pi}{4}\right)=\dfrac{1}{2}\\ < =>\left[{}\dfrac{x+\dfrac{\pi}{4}=\dfrac{\pi}{6}+k2\pi}{x+\dfrac{\pi}{4}=\dfrac{5\pi}{6}+k2\pi}}\\ < =>\left[{}\begin{matrix}x=\dfrac{-\pi}{12}+k2\pi\\x=\dfrac{7\pi}{12}+k2\pi\end{matrix}\right.\)