\(=\left(-\dfrac{1}{3}\right)^2\cdot1=\dfrac{1}{9}\)
\(\left(\dfrac{-1}{3}\right)^2\times\dfrac{4}{1}+\dfrac{7}{11}\times\left(\dfrac{-1}{3}\right)^2\)
\(=\dfrac{1}{9}\times4+\dfrac{7}{11}\times\dfrac{1}{9}\)
\(=\dfrac{1}{9}\times\left(4+\dfrac{7}{11}\right)\)
\(=\dfrac{1}{9}\times\dfrac{51}{11}\)
\(=\dfrac{17}{33}\)