Lời giải:
\(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right).\dfrac{5}{6}-17\)
\(=\left(4:\dfrac{4}{3}-\dfrac{1}{2}\right).\dfrac{5}{6}-17\)
\(=\left(3-\dfrac{1}{2}\right).\dfrac{5}{6}-17\)
\(=\dfrac{5}{2}.\dfrac{5}{6}-17\)
\(=\dfrac{25}{12}-17=-\dfrac{179}{12}\)
Vậy ...
\(\)\(\left(\dfrac{2^2}{\dfrac{4}{3}}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17=\left(\dfrac{4}{\dfrac{4}{3}}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17=\left(3-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17=\dfrac{5}{2}\cdot\dfrac{6}{5}-17=3-17=-14\)
Lời giải:
\(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right).\dfrac{6}{5}-17\)
\(=\left(4:\dfrac{4}{3}-\dfrac{1}{2}\right).\dfrac{6}{5}-17\)
\(=\left(3-\dfrac{1}{2}\right).\dfrac{6}{5}-17\)
\(=\dfrac{5}{2}.\dfrac{6}{5}-17\)
\(=3-17=-14\)
Chúc bạn học tốt!