Nhận xét : \(VT\ge0\)
\(\Rightarrow VT=2.\left(x+2\right)+2.\left(x-1\right)=2.\left(x+2+x-1\right)=2.\left(2x+1\right)=5\)
\(\Leftrightarrow2x+1=\frac{5}{2}\)
\(\Leftrightarrow2x=\frac{5}{2}-1\)
\(\Leftrightarrow2x=\frac{3}{2}\)
\(\Leftrightarrow x=\frac{3}{4}\)
Vậy : \(x=\frac{3}{4}\)