a)\(\left(2x-1\right)^5=32\)
\(\Rightarrow\left(2x-1\right)^5=2^5\)
\(\Rightarrow2x-1=2\)
\(\Rightarrow2x=3\Rightarrow x=\frac{3}{2}\)
b)\(\left(2x+1\right)^2=169\)
\(\Rightarrow\left(2x+1\right)^2=13^2=\left(-13\right)^2\)
\(\Rightarrow2x+1=13\) hoặc \(2x+1=-13\)
\(\Rightarrow2x=12\) hoặc \(2x=-14\)
\(\Rightarrow x=6\) hoặc \(x=-7\)
c)\(x^{100}=x\)
\(\Rightarrow x^{100}-x=0\)
\(\Rightarrow x\left(x^{99}-1\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x^{99}-1=0\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x^{99}=1\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0\\x=1\end{array}\right.\)
a, (2x-1)^5=32
(2x-1)^5=2^5
2x-1=2
2x=2+1
2x=3
x=3:2
x=1,5
Vậy x=1,5
b, (2x+1)^2=169
(2x+1)^2=13^2
2x+1=13
2x=13-1
2x=12
x=12:2
x=6
Vậy x=6
c, x^100=x
=>x=0
x=1
