a, Ta có : \(1,2=\dfrac{12}{10}=\dfrac{6}{5}\) ; \(3,36=\dfrac{84}{25}\)
=> \(1,2:3,36=\dfrac{6}{5}:\dfrac{84}{25}=\dfrac{5}{14}\)
b, Ta có : \(3\dfrac{1}{7}:2\dfrac{5}{14}=\dfrac{22}{7}:\dfrac{33}{14}=\dfrac{4}{3}\)
c,\(\dfrac{3}{8}:0,54=\dfrac{3}{8}:\dfrac{27}{50}=\dfrac{25}{36}\)