Question

1.Phân tích các đa thức sau thành nhân tử

a, x²+7x+10

b,x²-3x+2

c, x²-5x-24

d, 2x²-10x+12

Answer 1

d.

= 2x\(^2\)-4x-6x+12

=2x(x-2)-6(x-2)

=(2x-6)(x-2)

Answer 2

a.

= \(x^2\)+2x+5x+10

=x(x+2) +5(x+2)

=(x+5)(x+2)

Answer 3

b.

= x\(^2\)-x-2x+2

=x(x-1)-2(x-1)

= (x-2)(x-1)

Answer 4

c.

= x\(^2\)+3x-8x-24

=x(x+3) - 8(x+3)

= (x-8)(x+3)

Answer 5

a, \(x^2+7x+10=x^2+2x+5x+10\)

\(\Rightarrow x.\left(x+2\right)+5.\left(x+2\right)=\left(x+5\right).\left(x+2\right)\)

b, \(x^2-3x+2=x^2-x-2x+2\)

\(\Rightarrow x.\left(x-1\right)-2.\left(x-1\right)=\left(x-2\right).\left(x-1\right)\)

c, \(x^2-5x-24=x^2+3x-8x-24\)

\(\Rightarrow x.\left(x+3\right)-8.\left(x+3\right)=\left(x-8\right).\left(x+3\right)\)

d, \(2x^2-10x+12=2x^2-4x-6x+12\)

\(\Rightarrow2x.\left(x-2\right)-6\left(x-2\right)=\left(2x-6\right).\left(x-2\right)\)