Bài 3 :
Có liên quan tới casio nhá .
Ta có :
\(x^3-y^2=xy\)
\(\Leftrightarrow x^3=y^2+xy\)
\(\Leftrightarrow x^3+\dfrac{1}{4}x^2=y^2+xy+\dfrac{1}{4}x^2\)
\(\Leftrightarrow x^3+\left(\dfrac{1}{2}x\right)^2=\left(y+\dfrac{1}{2}x\right)^2\)
\(\Leftrightarrow y+\dfrac{1}{2}x=\sqrt{x^3+\left(\dfrac{1}{2}x\right)^2}\)
\(\Leftrightarrow y=\sqrt{x^3+\left(\dfrac{1}{2}x\right)^2}-\dfrac{1}{2}x\)
Nhập :
\(x=x+1:y=\sqrt{x^3+\left(\dfrac{1}{2}x\right)^2}-\dfrac{1}{2}x\)
\(\Rightarrow\left(x;y\right)=110;1100\)