\(=\sqrt{12+2\cdot\sqrt{2}\cdot\sqrt{3}+2\cdot\sqrt{2}\cdot1+2\cdot\sqrt{3}\cdot1}\)
\(=\sqrt{6+2\cdot\sqrt{2}\cdot\sqrt{3}+2\cdot\sqrt{2}\cdot1+2\cdot\sqrt{3}\cdot1+6}\)
\(=\sqrt{\left(\sqrt{3}+\sqrt{2}+1\right)^2+6}\)
\(=\sqrt{12+2\cdot\sqrt{2}\cdot\sqrt{3}+2\cdot\sqrt{2}\cdot1+2\cdot\sqrt{3}\cdot1}\)
\(=\sqrt{6+2\cdot\sqrt{2}\cdot\sqrt{3}+2\cdot\sqrt{2}\cdot1+2\cdot\sqrt{3}\cdot1+6}\)
\(=\sqrt{\left(\sqrt{3}+\sqrt{2}+1\right)^2+6}\)
\(\sqrt{2-\sqrt{3}}.\left(\sqrt{6}-\sqrt{12}\right).\left(2+\sqrt{3}\right)\)
\(\sqrt{2}.\sqrt{2-\sqrt{3}}.\left(\sqrt{3}+1\right)\)
\(\sqrt{6+2\sqrt{5}-\sqrt{29-12\sqrt{5}}}\)
\(\sqrt{\sqrt{5}-\sqrt{3-\sqrt{29-12\sqrt{5}}}}\)
Thực hiện phép tính:
D= \(\sqrt{9+6\sqrt{2}}\) - \(\sqrt{9-6\sqrt{2}}\) - \(\sqrt{21-12\sqrt{3}}\)
1: (a-3)√b^2/a^2-6*a+9 (a>3)
2: 1/3+a* √a^2+6a+9/b^2
3:√(a+1)^2 - 3a/a-2 * √a^2-4a+4/9 (a>2)
4: (3-√3)*(-2√3)+(3√3+1)^2
5: (2√3-3√2)^2 + √(12√6-5)^2
6: (4+√15)*(√10-√6)*√4-√15
7: √3-√5 * (√10 -√2)*(3+√5)
Mọi người giúp mk với
\(\dfrac{\sqrt{2}+\sqrt{3}+\sqrt{4}-\sqrt{6}-\sqrt{9}-\sqrt{12}}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
Rút gọn các biểu thức sau :
a,\(\dfrac{\sqrt{6}+\sqrt{10}}{\sqrt{21}+\sqrt{35}}\)
b,\(\dfrac{\sqrt{405}+3\sqrt{27}}{3\sqrt{3}+\sqrt{45}}\)
c,\(\dfrac{\sqrt{2}+\sqrt{3}+\sqrt{4}-\sqrt{6}-\sqrt{9}-\sqrt{12}}{\sqrt{2}+\sqrt{3}+\sqrt{4}}\)
d, D=\(\dfrac{2}{x^2-y^2}\cdot\sqrt{\dfrac{9\left(x^2+2xy+y^2\right)}{4}}\) \(\left(vớix\ne y,x\ne-y\right)\)
BÀI 1 : THỰC HIỆN PHÉP TÍNH
a, \(\left(1+\sqrt{3}-\sqrt[2]{2}\right)\times\left(1+\sqrt{3}+\sqrt[2]{2}\right)\)
b, \(\left(\dfrac{3}{2}\times\sqrt{6}+2\times\sqrt{\dfrac{2}{3}}-4\times\sqrt{\dfrac{3}{2}}\right)\times\left(3\times\sqrt{\dfrac{2}{3}}-\sqrt{12}-\sqrt{6}\right)\)
BÀI 2 : rút gọn
B = \(\sqrt{x+2\sqrt{2x-4}}+\sqrt{x-2\sqrt{2x-2}}\)
b1. Rút gọn
a)\(\frac{5\sqrt{6}+6\sqrt{5}}{\sqrt{5}+\sqrt{6}}\)
b) \(\frac{2\sqrt{7}-4\sqrt{3}}{3\sqrt{35}-6\sqrt{15}}\)
c) \(\frac{12\sqrt{10}-16\sqrt{14}}{6\sqrt{5}-8\sqrt{7}}\)
d) \(\frac{6\sqrt{6}-27}{2\sqrt{2}-3\sqrt{3}}\)
e) \(\frac{-4\sqrt{2}+3\sqrt{5}}{-2\sqrt{10}}\)
A)\(\left(3-2\sqrt{2}\right).\left(3+2\sqrt{2}\right)\) B) \(\sqrt{\left(\sqrt{3}-2\right)}^2-\sqrt{\left(\sqrt{3}+2\right)}^2\) C)\(\sqrt{3-2\sqrt[]{2}}-\sqrt{3+2\sqrt{2}}\)
D)\(\left(1+\sqrt{3}-\sqrt{2}\right).\left(1+\sqrt{3}+2\right)\)
E) \(\left(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\right)^2\) F)\(\sqrt{15-\sqrt{216}}+\sqrt{33-12\sqrt{6}}\)
H)\(\sqrt{8\sqrt{3}}-2\sqrt{25\sqrt{12}}+4\sqrt{\sqrt{192}}\)
So sánh 3√2 và 2√16. 1/4√12 và 6√1/7