ta có:\(\left(\dfrac{-1}{16}\right)^{10}=\left(\dfrac{1}{16}\right)^{10}=\left(\dfrac{1^4}{2^4}\right)^{10}=\left[\left(\dfrac{1}{2}\right)^4\right]^{10}=\left(\dfrac{1}{2}\right)^{40}=\dfrac{1^{40}}{12^{40}}=\dfrac{1}{2^{40}}\)
ta có:
\(\left(\dfrac{-1}{2}\right)^{500}=\left(\dfrac{1}{2}\right)^{500}=\dfrac{1^{500}}{2^{500}}=\dfrac{1}{2^{500}}\)
Vì 40<500
⇒2\(^{40}< 2^{500}\)
⇒\(\dfrac{1}{2^{40}}>\dfrac{1}{2^{500}}\)
⇒\(\left(\dfrac{-1}{16}\right)^{10}>\left(\dfrac{-1}{2}\right)^{500}\)
Vậy \(\left(\dfrac{-1}{16}\right)^{10}>\left(\dfrac{-1}{2}\right)^{500}\)
\(+,\left(\dfrac{-1}{16}\right)^{10}=\left(\dfrac{\left(-1\right)^4}{2^4}\right)^{10}=\left[\left(\dfrac{-1}{2}\right)^4\right]^{10}=\left(\dfrac{-1}{2}\right)^{40}\)
Vì 40<500→\(\left(\dfrac{-1}{2}\right)^{40}< \left(\dfrac{-1}{2}\right)^{500}hay\left(\dfrac{-1}{16}\right)^{10}< \left(\dfrac{-1}{2}\right)^{500}\)
