\(\left(x+\frac{1}{2}\right)^2=\frac{4}{25}\)
\(\left(x+\frac{1}{2}\right)^2=\left(\pm\frac{2}{5}\right)^2\)
\(x+\frac{1}{2}=\pm\frac{2}{5}\)
TH1:
\(x+\frac{1}{2}=\frac{2}{5}\)
\(x=\frac{2}{5}-\frac{1}{2}\)
\(x=\frac{4}{10}-\frac{5}{10}\)
\(x=-\frac{1}{10}\)
TH2:
\(x+\frac{1}{2}=-\frac{2}{5}\)
\(x=-\frac{2}{5}-\frac{1}{2}\)
\(x=-\frac{4}{10}-\frac{5}{10}\)
\(x=-\frac{9}{10}\)
Vậy \(x=-\frac{1}{10}\) hoặc \(x=-\frac{9}{10}\)
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