a, Với mọi giá trị của x;y ta có:
\(\left(3x-5\right)^{100}+\left(2y-1\right)^{200}\ge0\)
Để \(\left(3x-5\right)^{100}+\left(2y-1\right)^{200}=0\) thì
\(\left\{{}\begin{matrix}\left(3x-5\right)^{100}=0\\\left(2y-1\right)^{200}=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}3x-5=0\\2y-1=0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5}{3}\\y=\dfrac{1}{2}\end{matrix}\right.\)
Chúc bạn học tốt!!!
1, Ta có: \(\left\{{}\begin{matrix}\left(3x-5\right)^{100}\ge0\\\left(2y-1\right)^{200}\ge0\end{matrix}\right.\Rightarrow\left(3x-5\right)^{100}+\left(2y-1\right)^{200}\ge0\)
Mà \(\left(3x-5\right)^{100}+\left(2y-1\right)^{200}=0\)
\(\Rightarrow\left\{{}\begin{matrix}\left(3x-5\right)^{100}=0\\\left(2y-1\right)^{200}=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5}{3}\\y=\dfrac{1}{2}\end{matrix}\right.\)
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