Pt hoành độ giao điểm:
\(x^4-\left(3m+2\right)x^2+3m=-1\)
\(\Leftrightarrow x^4-1-\left(3m+2\right)x^2+3m+2=0\)
\(\Leftrightarrow\left(x^2-1\right)\left(x^2+1\right)-\left(3m+2\right)\left(x^2-1\right)=0\)
\(\Leftrightarrow\left(x^2-1\right)\left(x^2-3m-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2=1\\x^2=3m+1\end{matrix}\right.\)
Để bài toán thỏa mãn \(\Leftrightarrow3m+1>\frac{1}{4}\)
\(\Leftrightarrow m>-\frac{1}{4}\)