Question

1) phân tích đa thức thành nhân tử

\(x^2-2xy+y^2-xz+yz\)

Answer 1

\(x^2-2xy+y^2-xz+yz\)

\(=\left(x-y\right)^2-z\left(x-y\right)\)

\(=\left(x-y\right)\left(x-y-z\right)\)

Answer 2

\(x^2-2xy+y^2-xz+yz=\left(x^2-2xy+y^2\right)-\left(xz-yz\right)=\left(x-y\right)^2-z\left(x-y\right)=\left(x-y\right)\left(x-y-z\right)\)

Answer 3

x² - 2xy + y² - xz + yz = (x-y)² - xz + yz 

                                    = (x-y)² - (xz - yz )

                                    = (x-y)² - z(x-y)

                                    =  (x-y)(x-y-z)