\(-\dfrac{1}{2}-\left(x+\dfrac{3}{4}\right)=-\dfrac{5}{4}\)
\(\Rightarrow-\dfrac{1}{2}-x-\dfrac{3}{4}=-\dfrac{5}{4}\)
\(\Rightarrow-x=-\dfrac{5}{4}+\dfrac{1}{2}+\dfrac{3}{4}=-\dfrac{5}{4}+\dfrac{2}{4}+\dfrac{3}{4}=0\)
=> x = 0
\(\dfrac{-1}{2} - (x+\dfrac{3}{4}) = \dfrac{-5}{4} \)
⇒ \(\dfrac{-1}{2} - x-\dfrac{3}{4} = \dfrac{-5}{4} \)
⇒ \(( -x)-\dfrac{3}{4} = \dfrac{-5}{4} + \dfrac{1}{2}\)
⇒ \(( -x)-\dfrac{3}{4} = \dfrac{-3}{4}\)
⇒ \(-x= \dfrac{-3}{4}+\dfrac{3}{4} \)
⇒ \(x=0\)