Bài 2 : Rút gọn biểu thức :
\(\dfrac{2}{1+\sqrt{2}}+\dfrac{1}{3+2\sqrt{2}}=\dfrac{2}{1+\sqrt{2}}+\dfrac{1}{\left(1+\sqrt{2}\right)^2}\)
\(=\dfrac{2\left(1+\sqrt{2}\right)+1}{\left(1+\sqrt{2}\right)^2}=\dfrac{2+2\sqrt{2}+1}{\left(1+\sqrt{2}\right)^2}\)
\(=\dfrac{\left(\sqrt{2}+1\right)^2}{\left(1+\sqrt{2}\right)^2}=1\)