13:
x^2<=4
=>x^2-4<=0
=>(x-2)(x+2)<=0
=>-2<=x<=2
(2x^2-3x)(x^2-x-6)=0
=>x(2x-3)(x-3)(x+2)=0
=>\(x\in\left\{0;\dfrac{3}{2};3;-2\right\}\)
A={x thuộc Z;z^2<=4}
=>A={0;1;-1;2;-2}
B={x thuộc Z|(2x^2-3x)(x^2-x-6)=0}
=>B={0;3;-2}
(A hợp B)\(A giao B)
={0;1;-1;2;-2;3}\{0;-2}
={1;-1;2;3}