Question

Answer 1

`(0,4x +1)/(x-1) = (2x-1)/(5x+3)`

`<=> (0,4x +1)(5x+3) = (x-1)(2x-1)`

`<=> 2/5x(5x+3) + 5x+3 = x(2x-1) -(2x-1)`

`<=> 2x^2 + 6/5x +5x+3 = 2x^2 - x -2x +1`

`<=> 2x^2 + 6/5x +5x -2x^2 +x +2x = 1-3`

`<=> 46/5x = -2`

`<=> x = -2 * 5/46 `

`x = -10/46 = -5/23`

Vậy `x=-5/23`

Answer 2

\(\Leftrightarrow\left(0.4x+1\right)\left(5x+3\right)=\left(2x-1\right)\left(x-1\right)\)

\(\Leftrightarrow2x^2+1.2x+5x+3=2x^2-3x+1\)

=>6,2x+3=-3x+1

=>9,2x=-2

hay x=-1/4,6=-10/46=-5/23