Question

Answer 1

a: \(4^{2222}=16^{1111}=2^{4444}\)

b: Đặt x/5=y/3=k

=>x=5k; y=3k

Ta có: xy=60

=>15k²=60

=>k²=4

TH1: k=2

=>x=10; y=6

TH2: k=-2

=>x=-10; y=-6

Answer 2

a) Có: \(4^{2222}=\left(2^2\right)^{2222}=2^{4444}=2^{4444}\)

b) Đặt \(\dfrac{x}{5}=\dfrac{y}{3}=k\Rightarrow x=5k,y=3k\)

Có: \(5k.3k=60\)

\(\Rightarrow15k^2=60\)

\(\Rightarrow k^2=4\Rightarrow k=\pm2\)

TH1: k=2

\(\Rightarrow\left\{{}\begin{matrix}x=5k=10\\y=3k=6\end{matrix}\right.\)

TH2: k=-2

\(\Rightarrow\left\{{}\begin{matrix}x=5k=-10\\y=3k=-6\end{matrix}\right.\)

Answer 3

\(a,4^{2222}=\left(4^2\right)^{1111}=16^{1111}\)

\(2^{4444}=\left(2^4\right)^{1111}=16^{1111}\)

\(16^{1111}=16^{1111}\Leftrightarrow4^{2222}=2^{4444}\)