\(\lim\limits_{x\rightarrow-3}\dfrac{x^4-6x^2-27}{x^3+3x^2+x+3}=\lim\limits_{x\rightarrow-3}\dfrac{\left(x+3\right)\left(x-3\right)\left(x^2+3\right)}{\left(x+3\right)\left(x^2+1\right)}=\lim\limits_{x\rightarrow-3}\dfrac{\left(x-3\right)\left(x^2+3\right)}{x^2+1}=\dfrac{-6.12}{10}=...\)