\(=\dfrac{\left(-2\right)^{44}\cdot\left(-5\right)^{40}}{\left(-2\right)^{41}\left(-5\right)^{41}}=\dfrac{\left(-2\right)^3}{-5}=\dfrac{8}{5}\)
\(\dfrac{16^{11}.5^{40}}{\left(-10\right)^{41}}=\dfrac{8^{11}.2^{11}.\left(-5\right)^{40}}{\left(-5\right)^{41}.2^{41}}=\dfrac{\left(2^3\right)^{11}}{-5.2^{30}}=\dfrac{2^{33}}{-5.2^{30}}=\dfrac{2^3}{-5}=-\dfrac{8}{5}\)