\(a,\left(2x-x^2\right)\left(3x-2\right)=0\\ \Rightarrow x\left(2-x\right)\left(3x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=2\\x=\dfrac{2}{3}\end{matrix}\right.\Rightarrow A=\left\{0;\dfrac{2}{3};2\right\}\\ b,2x^3-3x^2-5x=0\\ \Rightarrow x\left(2x-5\right)\left(x+1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{5}{2}\left(ktm\right)\\x=-1\end{matrix}\right.\Rightarrow B=\left\{-1;0\right\}\)
\(c,2x^2-75x-77=0\\ \Rightarrow\left(2x-77\right)\left(x+1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{77}{2}\left(ktm\right)\\x=-1\end{matrix}\right.\Rightarrow C=\left\{-1\right\}\\ d,\left(x^2-x-2\right)\left(x^2-9\right)=0\\ \Rightarrow\left(x-2\right)\left(x+1\right)\left(x-3\right)\left(x+3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=2\\x=-1\\x=3\\x=-3\end{matrix}\right.\Rightarrow D=\left\{-3;-1;2;3\right\}\)
