a) C = \(\frac{\left(2^3\right)^{10}.\left(2^2\right)^{10}}{\left(2^3\right)^4.\left(2^2\right)^{11}}\)

= \(\frac{2^{3.10}.2^{2.10}}{2^{3.4}.2^{2.11}}\)

= \(\frac{2^{30}.2^{20}}{2^{12}.2^{22}}\)

= \(\frac{2^{50}}{2^{34}}\) = \(\frac{2^{16}.2^{34}}{1.2^{34}}\) = 2¹⁶

Giải :

-3 = -3

2 = 2

2,13 = 2,13

-√2 = -1,414

\(-\frac{3}{7}\)= -0,428

⇒ -3 < -√2 < \(-\frac{3}{7}\) < 2 < 2,13

CHÚC BẠN HỌC TỐT ^_^

a)|x+9|-7=15

|x+9|=15+7

|x+9|=22

Suy ra x+9=22 hoặc x+9=-22

Suy ra x=13;-31

b)24-(x-6)=-3+25

24-(x-6)=22

x-6=24-22

x-6=2

x=2+6

x=8

\(\frac{2^{7x}}{2^{3x}}=64\)

\(\frac{2^7.2^x}{2^3.2^x}=64\)

\(\frac{2^x}{2^x}=64:\frac{2^7}{2^3}\)

\(\frac{2^x}{2^x}=64.\frac{2^3}{2^7}\)

\(\frac{2^x}{2^x}=\frac{64.8}{2^7}=\frac{512}{128}=4\)

⇒ 1 = 4

⇒ x ∈ ∅

CHÚC BẠN HỌC TỐT ^_^