(3x-6)=3⁴:3

(3x-6)=27

3x=33

x=11

\(P=\left(\left|x-3\right|+2\right)^2+\left|y+3\right|+2017\) 

Có: \(\left(\left|x-3\right|+2\right)^2\ge4\)

\(\left|y+3\right|\ge0\)

\(\Rightarrow\left(\left|x-3\right|+2\right)^2+\left|y+3\right|+2017\ge2021\)

\(\Leftrightarrow\hept{\begin{cases}\left(\left|x-3\right|+2\right)^2=4\\y+3=0\end{cases}}\Rightarrow\hept{\begin{cases}x-3=0\\y=-3\end{cases}}\Rightarrow\hept{\begin{cases}x=3\\y=-3\end{cases}}\)

Vậy: \(Min_P=2021\) tại \(\hept{\begin{cases}x=3\\y=-3\end{cases}}\)

b) Để f(x)=-11

Ta có: 2.x-5=-11

2x=-11+5

2.x=-6

x =-6:2

x=-3

Vậy để f(x)=11 thì x=-3

BC=15cm;CD=24CM;AD=20CM.

(15+24+20):3=19CM

19CM. 

K CHO MINH NHA