\(\left\{{}\begin{matrix}x^2-3x\sqrt{y}+3\sqrt{y}=1\\\frac{16}{x}-3\sqrt{y}=5\end{matrix}\right.\)

\(\left\{{}\begin{matrix}3x-y^2-2\sqrt{\left(x-2\right)\left(y+1\right)}=-5\\-2x+y^2+y=6\end{matrix}\right.\)

\(\sqrt{2-3x}=-3x^2+7x-1\)

\(\left\{{}\begin{matrix}2\left(x+\sqrt{2x+y}\right)=3-y\\x^2-2xy-y^2=2\end{matrix}\right.\)