Tìm m để hệ : \(\left\{{}\begin{matrix}mx+2y=m\\\left(m-1\right)x+\left(m-1\right)y=1\end{matrix}\right.\) có nghiệm

tìm m để hệ : \(\left\{{}\begin{matrix}mx+y=m\\x+my=m^2\end{matrix}\right.\)có nghiệm duy nhất

\(\left\{{}\begin{matrix}\left(4x^2+1\right)x+\left(y-3\right)\sqrt{5-2y}=0\\4x^2+y^2=5\end{matrix}\right.\)

\(\left\{{}\begin{matrix}x^2+y+x^3y+xy^2+xy=-\dfrac{5}{4}\\x^4+y^2+xy\left(1+2x\right)=-\dfrac{5}{4}\end{matrix}\right.\)

\(\left\{{}\begin{matrix}xy+x+1=7y\\x^2y^2+xy+1=13y^2\end{matrix}\right.\)

\(\left\{{}\begin{matrix}2x^2-y^2=1\\xy+x^2=2\end{matrix}\right.\)

giải hệ: \(\left\{{}\begin{matrix}x+y=2\\2x^2+y+xy=8\end{matrix}\right.\)