\(2Ca+O_2\underrightarrow{t^o}2CaO\)
\(2Cu+O_2\underrightarrow{t^o}2CuO\)
Gọi \(\left\{{}\begin{matrix}n_{Ca}:a\left(mol\right)\\n_{Cu}:b\left(mol\right)\end{matrix}\right.\)
\(n_{O_2}=\dfrac{5,656}{22,4}=0,2525\left(mol\right)\Rightarrow a+b=0,505\left(I\right)\)
\(m_{hh}=25g\Rightarrow40a+64b=25\left(II\right)\)
Từ (I) và (II) \(\Rightarrow\left\{{}\begin{matrix}a=0,305\\b=0,2\end{matrix}\right.\)
\(\Rightarrow\%m_{Ca}=\dfrac{0,305.40}{25}.100\%=48,8\%\Rightarrow\%m_{Cu}=51,2\%\)
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