giải nhanh trong 10 phút được thưởng
Tìm x
\(1.\left(x+0,7\right)^3=-27\)
\(2.\left(2x-1\right)^{10}=49^5\)
\(3.\left(\frac{2}{3}x-\frac{1}{3}\right)^5=\frac{1}{243}\)
\(4.\left(\frac{2}{5}-3x\right)^2=\frac{9}{25}\)
CÁC BẠN GIÚP MÌNH VỚI !!!!!
bài 2
q,\(\frac{11}{3}-\left(\frac{5}{42}-x\right)\)
b,\(x+\frac{1}{3}=\frac{2}{5}-\left(\frac{-1}{3}\right)\)
c,\(\frac{-2}{3}x+\frac{5}{7}=\frac{3}{10}\)
d,\(\frac{3}{7}-x=\frac{1}{4}-\left(\frac{-3}{5}\right)\)
bài5
(x+1) (x-2)<0 (x-2) (x+\(\frac{2}{3}\))>0
\(\frac{3}{7}-x=\frac{1}{4}-\left(\frac{-3}{5}\right)\)
giúp mình với làm ơn
Tìm x:
a) (x-1)3-(-\(\frac{3}{4}\))=\(\frac{7}{8}\)
b)3x-1=\(\frac{1}{243}\)
bài3
a,\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
b,\(2x.\left(x\frac{-1}{7}\right)=0\)
c,\(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
bài 4:
a,|x-1,5|=2 b,|\(x+\frac{4}{15}\)|-|-3,75|=-|-2,15|
c,|\(x+\frac{3}{4}\)| - \(\frac{1}{2}\)=0
Bài 1 : Tìm x
a, (x + \(\frac{1}{2}\))\(^2\)= \(\frac{1}{100}\)
b, (x - \(\frac{1}{5}\))\(^{^3}\)= -27
c, (2x + 7 ) \(^{^{ }3}\)= -1
1. Tìm số nguyên x, biết
a) 3^−1.4^x+3.4^x=5/3.2^7
1. Tìm số nguyên x, y biết:
a) \(^{3^{4-x}}=27\)
b) \(^{3^{-1}}.^{4^x}+3.^{4^x}=\dfrac{5}{3}.^{2^7}\)
4. Tìm x biết:
a) (3x - 7)5 = 0;
b) \(\frac{1}{4}\) - (2x - 1)2 = 0;
c) \(\frac{1}{16}\) - (5 - x)3 = \(\frac{31}{64}\);
d) 2x = (3,8)3 : (-3,8)2;
e) \(\left(\frac{27}{64}\right)^9\). x = \(\left(-\frac{3}{4}\right)^{32}\);
f) \(5^{\left(x+5\right)\left(x^2-4\right)}\) = 1;
g) (x - 2,5)2 = \(\frac{4}{9}\);
h) \(\left(2x+\frac{1}{3}\right)^3=\frac{8}{27}\)
