Question

Xét dấu

g(x) = -6x³ - 19x² - 11x+6

Answer 1

\(g\left(x\right)=\left(x+2\right)\left(1-3x\right)\left(2x+3\right)\)

\(g\left(x\right)=0\) khi \(\left[{}\begin{matrix}x=-2\\x=-\frac{3}{2}\\x=\frac{1}{3}\end{matrix}\right.\)

\(g\left(x\right)>0\) khi \(\left[{}\begin{matrix}x< -2\\-\frac{3}{2}< x< \frac{1}{3}\end{matrix}\right.\)

\(g\left(x\right)< 0\) khi \(\left[{}\begin{matrix}-2< x< -\frac{3}{2}\\x>\frac{1}{3}\end{matrix}\right.\)