Question

\(x+3+\sqrt{x^2-6x+9}\) biết (x\(\le\) 3) giúp em với ạ

Answer 1

\(x+3+\sqrt{x^2-6x+9}=x+3+\sqrt{\left(x-3\right)^2}=x+3+\left|x-3\right|=x+3+3-x=6\)

Answer 2

\(x+3+\sqrt{x^2-6x+9}\)

\(=x+3+\sqrt{\left(x-3\right)^2}\)

\(=x+3+\left|x-3\right|=x+3+\left|3-x\right|\)

\(=x+3+3-x=6\)