\(\left(x+2,5\right):2\dfrac{1}{2}-1,5=-1\dfrac{1}{4}\\ < =>\left(x+\dfrac{5}{2}\right):\dfrac{5}{2}-\dfrac{3}{2}=-\dfrac{5}{4}\\ =>\left(x+\dfrac{5}{2}\right).\dfrac{2}{5}=-\dfrac{5}{4}+\dfrac{3}{2}=\dfrac{1}{4}\\ =>x+\dfrac{5}{2}=\dfrac{1}{4}:\dfrac{2}{5}=\dfrac{5}{8}\\ =>x=\dfrac{5}{8}-\dfrac{5}{2}=-\dfrac{15}{8}\)
\(\left(x+2,5\right):2\dfrac{1}{2}-1,5=-1\dfrac{1}{4}\)
\(\Leftrightarrow\left(x+\dfrac{5}{2}\right):\dfrac{5}{2}-\dfrac{3}{2}=\dfrac{-5}{4}\)
\(\left(x+\dfrac{5}{2}\right):\dfrac{5}{2}=\dfrac{-5}{4}+\dfrac{3}{2}\)
\(\left(x+\dfrac{5}{2}\right):\dfrac{5}{2}=\dfrac{1}{4}\)
\(x+\dfrac{5}{2}=\dfrac{1}{4}.\dfrac{5}{2}\)
\(x+\dfrac{5}{2}=\dfrac{5}{8}\)
\(x=\dfrac{5}{8}-\dfrac{5}{2}\)
\(x=\dfrac{-15}{8}\)
Vậy \(x=\dfrac{-15}{8}\)
