\(x^2+x+1=0\)
Ta có :
\(x^2+x+1\\ =\left(x^2+2\cdot x\cdot\dfrac{1}{2}+\dfrac{1}{4}\right)+\dfrac{3}{4}\\ =\left(x+\dfrac{1}{2}\right)^2+\dfrac{3}{4}>0\forall x\)
Vậy pt trên vô nghiệm
Tim x thuoc Q
a, (x+1)(x-2)<0
b, (x-2)(x+2/3)>0
a) Tim so nguyen a de a2 + a + 3 / a+1 la so nguyen.o cho x-2xy+y=0
b)Tim so nguyen x,y sao cho x-2xy+y=0.
1) tim x thuoc Q
A)|x|=2,1
B)|x|=1 va2/5
C)|x|=17/9 va x<0
D)|x|=0,35 va x>0
2)tim x
A) |x-1,7=2,3
B)|x+3/4|-1/3=0
cac bn giup mih nha 
tim x , y :
/ x + 3y -1 / + / 2y - \(\frac{1}{2}\) /^200 = 0
a)Tim so nguyen x va y biet :
5/x+y/4=1/8
b)Tim so nguyen x de A co gia tri la 1 so nguyen biet :
A=(căn x +1) /(căn x -3) (x lớn hơn hoặc bằng 0)
tim x
\(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)
1.Cho A=1/1.2+1/3.4+...+1/99.100
C/m :7/12<A<5/6
2.Tim x:
a.2/(x+2)(x+4)+4/(x+4)(x+8)+6/(x+8)(x+14)
b.x-10/30+x-14/43+x-5/95+x-148/8=0
Lam giup minh nhe
Minh dang can gap
tim xEz biet:
a)\(x^2+\left(y-\frac{1}{4}\right)^4=6\)
b)\(x+\left(\frac{-31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
c)\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
tim x , y :
2 / x - 5 / ^4 + 5 / 2y - 7 / ^ 5 = 0
