Ta có :
\(x^2-9+\left(x-3\right)^2=\left(x-3\right)\left(x+3\right)+\left(x-3\right)^2=\left(x-3\right)\left(x+3+x-3\right)=2x\left(x-3\right)\)
\(x^2-9+\left(x-3\right)^2=\left(x-3\right)\left(x+3\right)+\left(x-3\right)^2=\left(x-3\right)\left(x+3+x-3\right)=2x\left(x-3\right)\)
CHÚC BẠN HỌC GIỎI