Question

(x^2-4)(2x+3)=0

Answer 1

Đề yêu cầu gì vậy em?

Answer 2

=>(x-2)(x+2)(2x+3)=0

=>\(x\in\left\{2;-2;-\dfrac{3}{2}\right\}\)

Answer 3

`(x^2-4)(2x+3)=0`

`<=>(x-2)(x+2)(2x+3)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+2=0\\2x+3=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\\2x=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\\x=-\dfrac{3}{2}\end{matrix}\right.\)

vậy phương trình có ngiệm \(x=\left\{2;-2;-\dfrac{3}{2}\right\}\)