Question

(x^2-3)^2=16

Answer 1

\(\left(x^2-3\right)^2=16\)

\(\Leftrightarrow\left(x^2-3\right)^2=4^2=\left(-4^2\right)\)

\(\Leftrightarrow\left[{}\begin{matrix}x^2-3=4\\x^2-3=-4\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x^2=7\\x^2=-1\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x=\sqrt{7}\\x=-\sqrt{7}\end{matrix}\right.\\x\in\varnothing\end{matrix}\right.\)

Vậy ....;

Answer 2

(x²-3)²=16

=> x²-3 = 4

x² = 4+3

x² = 7

=> x vô nghiệm