x2 -10x +25 = 0
(x-5)2 = 0
x - 5 = 0
x = 5
\(x^2-10x=-25\)
\(\Leftrightarrow x^2-10x+25=0\)
\(\Leftrightarrow\left(x-5\right)^2=0\)
\(\Leftrightarrow x-5=0\)
\(\Leftrightarrow x=5\)
x2 - 10x = -25
=> x2 - 10x + 25 = 0
(x - 5)2 = 0
x - 5 = 0
x = 0 + 5
x = 5
Vậy x = 5