Ta có: \(\left|x\right|-\left(6-\left|x\right|\right)=-4\)
\(\Leftrightarrow\left|x\right|-6+\left|x\right|=-4\)
\(\Leftrightarrow2\left|x\right|-6=-4\)
\(\Leftrightarrow2\left|x\right|=2\)
\(\Leftrightarrow\left|x\right|=1\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)
Vậy: \(x\in\left\{1;-1\right\}\)