\(\left(\dfrac{x-2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6\Rightarrow\left(\dfrac{x-2}{9}\right)^3=\left(\dfrac{2}{3}\right)^{2^3}\Rightarrow\left(\dfrac{x-2}{9}\right)^3=\left(\dfrac{4}{9}\right)^3\Rightarrow\dfrac{x-2}{9}=\dfrac{4}{9}\Rightarrow x-2=4\Rightarrow x=6\)
\(\left(\dfrac{x-2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6\)
\(\Rightarrow\dfrac{\left(x-2\right)^3}{9^3}=\dfrac{2^6}{3^6}\)
\(\Rightarrow\dfrac{\left(x-2\right)^3}{9^3}=\dfrac{\left(2^2\right)^3}{\left(3^2\right)^3}\)
\(\Rightarrow\dfrac{x-2}{9}=\dfrac{2^2}{3^2}\)
\(\Rightarrow\dfrac{x-2}{9}=\dfrac{4}{9}\)
\(\Rightarrow x-2=4\)
\(x=4+2\)
\(x=6\)
Vậy:\(x=6\)
làm giúp mình câu 1 thôi nha CẢm ơn nhìuuuu
giúp mình nha ! cảm ơn.