Question

(x-1/2)^2+1/4=5/16

Answer 1

\(\left(x-\dfrac{1}{2}\right)^2+\dfrac{1}{4}=\dfrac{5}{16}\)

\(\left(x-\dfrac{1}{2}\right)^2=\dfrac{5}{16}-\dfrac{1}{4}\)

\(\left(x-\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)

\(\left(x-\dfrac{1}{2}\right)^2=\left(\dfrac{1}{4}\right)^2=\left(\dfrac{-1}{4}\right)^2\)\

\(x-\dfrac{1}{2}=\dfrac{1}{4}\) hay \(\left(x-\dfrac{1}{2}\right)=\dfrac{-1}{4}\)

\(x=\dfrac{1}{2}+\dfrac{1}{4}=\dfrac{3}{4}\) hay \(x=\dfrac{1}{2}+\left(\dfrac{-1}{4}\right)=\dfrac{1}{4}\)

Vậy \(x\in\left\{\dfrac{1}{4};\dfrac{3}{4}\right\}\)