Question

(x-1)^2018 + (y-2)^2020 = 0

Answer 1

+ \(\left\{{}\begin{matrix}\left(x-1\right)^{2018}\ge0\forall x\\\left(y-2\right)^{2020}\ge0\forall y\end{matrix}\right.\)

\(\Rightarrow\left(x-1\right)^{2018}+\left(y-2\right)^{2020}\ge0\forall x,y\)

Dấu "=" xảy ra \(\Leftrightarrow\left\{{}\begin{matrix}\left(x-1\right)^{2018}=0\\\left(y-2\right)^{2020}=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=2\end{matrix}\right.\)