a) \(2,\left(15\right)=2+0,\left(15\right)=2+0,\left(01\right).15=2+\frac{1}{99}.15=2+\frac{5}{33}=\frac{71}{33}\)
b) \(2,\left(5\right)=2+0,\left(5\right)=2+0,\left(1\right).5=2+\frac{1}{9}.5=2+\frac{5}{9}=\frac{23}{9}\)
a) 2,(15) = 2 + 0,(15) = 2 + \(\frac{15}{99}\) = \(\frac{198}{99}\) + \(\frac{15}{99}\) = \(\frac{213}{99}\) = \(\frac{71}{33}\)
b) 2,(5) = 2 + 0,(5) = 2 + \(\frac{5}{9}\) = \(\frac{18}{9}\) + \(\frac{5}{9}\) = \(\frac{23}{9}\)