x(x-1) -(x-1) = x(x-1) -1(x-1) = (x-1)(x-1) = (x-1)2
Chịu thua!!!
\(x\left(x-1\right)-\left(x-1\right)\)
\(=x\left(x-1\right)-1\left(x-1\right)\)
\(=\left(x-1\right)\left(x-1\right)\)
Phương trình : \(\dfrac{1}{\left(x-1\right)\left(x-2\right)}+\dfrac{1}{\left(x-2\right)\left(x-3\right)}=\dfrac{1}{\left(x-3\right)\left(x-4\right)}+\dfrac{1}{\left(x-1\right)\left(x-4\right)}\)
Tìm x : \(\left(x-3\right)^2-\left(2x+1\right)^2-2\left(x-1\right)\left(x+2\right)=3\left(x-3\right)-\left(4x-1\right)\left(x+2\right)\)
a,\(\left|x+\frac{1}{2}\right|+\left|x+\frac{1}{3}\right|+\left|x+\frac{1}{6}\right|=4x\)
b,\(\frac{7}{\left(x+3\right)\left(x+10\right)}+\frac{11}{\left(x+10\right)\left(x+21\right)}+\frac{13}{\left(x+21\right)\left(x+34\right)}=\frac{x}{\left(x+3\right)\left(x+34\right)}\)
rut gon
\(\left(3x-1\right)^2+2\left(9x^2-1\right)+\left(3x+1\right)^2\)
\(\left(x^2-1\right)\left(x+3\right)-\left(x-3\right)\left(x^3+3x+9\right)\)
\(\left(x+4\right)\left(x-4\right)-\left(x-4\right)^2\)
Tìm x:
\(\left(x-1\right)^3-2\left(x-1\right)\left(x+2\right)=\left(x+2\right)^3-3\left(x-1\right)^2+2\left(x+2\right)^2\)
Tìm x : \(\left(x-3\right)^2-\left(2x+1\right)^2-2\left(x-1\right)\left(x+2\right)=3\left(x-3\right)-\left(4x-1\right)\left(x+2\right)\)
Tìm x: \(\frac{\left(x-2\right)^2}{2}-4\frac{1}{3}\left(x+3\right)^2=\frac{1}{4}\left(x-1\right)\left(x-2\right)-2\left(3x-1\right)\left(2+3x\right)\)
\(A=\left|4x-\frac{7}{3}\right|+2004\)
\(B=\left|x-1\right|+\left|x-2\right|+\left|x-3\right|+\left|x-4\right|\)
\(C=\left|x\right|+\left|x-1\right|+\left|x-2\right|+....+\left|x+99\right|\)
Tìm x: \(3\left(x-2\right)^2-1\frac{1}{4}\left(1+3x\right)^2=1\frac{1}{3}\left(x-1\right)\left(3-x\right)-1\frac{1}{6}x\left(x-3\right)\)
