Bài 1 :
\(n_{Mg}=a\left(mol\right),n_{Zn}=b\left(mol\right)\)
\(m_{hh}=24a+65b=31.5\left(g\right)\left(1\right)\)
\(n_{H_2}=\dfrac{17.92}{22.4}=0.8\left(mol\right)\)
\(Mg+H_2SO_4\rightarrow MgSO_4+H_2\)
\(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)
\(n_{H_2}=a+b=0.8\left(mol\right)\left(2\right)\)
\(\left(1\right),\left(2\right):a=0.5,b=0.3\)
\(m_{Mg}=0.5\cdot24=12\left(g\right)\)
\(m_{Zn}=0.3\cdot19.5\left(g\right)\)
\(n_{H_2SO_4}=n_{H_2}=0.8\left(mol\right)\)
\(C\%H_2SO_4=\dfrac{0.8\cdot98}{300}\cdot100\%=26.13\%\)
Đúng 1
Bình luận (0)
