Question

Trung Hòa 50 gam dung dịch axit axetic 6% cần vừa đủ V ml dung dịch NaOH 2M giá trị v là

Answer 1

CH3COOH + NaOH $\to$ CH3COONa + H2O

n NaOH = n CH3COOH = 50.6%/60 = 0,05(mol)

=> V dd NaOH = 0,05/2 = 0,025(lít) = 25(ml)

Answer 2

\(n_{CH_3COOH}=\dfrac{50\cdot6}{100\cdot60}=0.05\left(mol\right)\)

\(CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O\)

\(0.05.................0.05\)

\(V_{NaOH}=\dfrac{0.05}{2}=0.025\left(l\right)\)