=12/13+7-8+1/13
=(12/13+1/13)+(7-8)
=1+(-1)
=0
=12/13+7-8+1/13
=(12/13+1/13)+(7-8)
=1+(-1)
=0
B= \(\left(\dfrac{12}{13}+\dfrac{1}{13}\right)\)+7-8
B=0
B=12/13 + 7 + (-8) + 1/13
B=(12/13 + 1/13) + (-8 + 7)
B=1 + (-1)
B=0
B =\(\dfrac{12}{13}\) + 7 -8+\(\dfrac{1}{13}\)
B =(\(\dfrac{12}{13}\)+\(\dfrac{1}{13}\))+(7-8)
B =(-1)+1
B =0
Ta có: \(B=\left(\dfrac{12}{13}+7\right)+\left(-8+\dfrac{1}{13}\right)\)
\(=\left(\dfrac{12}{13}+\dfrac{1}{13}\right)+\left(7-8\right)\)
\(=1-1=0\)