a) \(\dfrac{-4}{6}\)
b) \(\dfrac{1}{3}\)-\(\dfrac{20}{60}\)
= 0
c) \(-20^2\)+(\(-50^3\))
= -400 + (-125000)
=-125400
d) \(\dfrac{-2}{7}\)+\(\dfrac{15}{35}\)
= \(\dfrac{-10}{35}\)+\(\dfrac{15}{35}\)
= \(\dfrac{5}{35}\)=\(\dfrac{1}{7}\)
a) \(\dfrac{-5}{6}+\dfrac{1}{6}=\dfrac{-5+1}{6}=\dfrac{-4}{6}=\dfrac{-2}{3}\)
b) \(\dfrac{1}{3}-\dfrac{5}{4}\cdot\dfrac{4}{15}=\dfrac{1}{3}-\dfrac{1}{3}=0\)
c) \(4\cdot\left(-5\right)^2+\left(-2\right)^3\cdot25=4\cdot25-8\cdot25=100-200=-100\)
d) \(\dfrac{-2}{7}+\dfrac{1}{5}:\dfrac{7}{15}=\dfrac{-2}{7}+\dfrac{1}{5}\cdot\dfrac{15}{7}=\dfrac{-2}{7}+\dfrac{3}{7}=\dfrac{1}{7}\)