\(\dfrac{5}{3}+\dfrac{5}{12}+\dfrac{5}{20}+\dfrac{5}{30}+...+\dfrac{5}{9900}=\dfrac{5}{3}+5\left(\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{99.100}\right)=\dfrac{5}{3}+5\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{99}-\dfrac{1}{100}\right)=\dfrac{5}{3}+5\left(\dfrac{1}{3}-\dfrac{1}{100}\right)=3\dfrac{23}{60}\).