Lời giải:
Ta có:
\(A=\left(\frac{1}{3}-\frac{5}{6}\right)^2:(-\frac{5}{12})-1,15\)
\(A=\left(\frac{2-5}{6}\right)^2:(-\frac{5}{12})-1,15\)
\(A=\left(-\frac{1}{2}\right)^2:(-\frac{5}{12})-1,15\)
\(A=\frac{1}{4}:(-\frac{5}{12})-1,15\)
\(A=-\frac{3}{5}-1,15\)
\(A=-0,6-1,15\)
\(A=-1,75\)
Chúc bạn học tốt!
Tick cho mik nhé!
\(\left(\frac{1}{3}-\frac{5}{6}\right)^2:\left(-\frac{5}{12}\right)-1,15\)
\(=\left(-\frac{1}{2}\right)^2:\left(-\frac{5}{12}\right)-\frac{23}{20}\)
\(=\frac{1}{4}:\left(-\frac{5}{12}\right)-\frac{23}{20}\)
\(=\left(-\frac{3}{5}\right)-\frac{23}{20}\)
\(=-\frac{7}{4}.\)
Chúc bạn học tốt!
